BSc Second Year (Sem 3 & 4) Chemistry – Daily Revision MCQ (English Medium)
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The Langmuir adsorption isotherm is based on the assumption that adsorption forms:
Chapter 1: Adsorption and Surface Chemistry
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Answer: B. A monolayer on a uniform surface
Langmuir assumed a fixed number of equivalent sites, each holding one molecule, so adsorption stops at a monolayer.Using the phase rule F = C − P + 2, the number of degrees of freedom at the triple point of water is:
Chapter 2: Phase Equilibria
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Answer: A. 0
Water: C = 1, P = 3 (ice, water, vapour), so F = 1 − 3 + 2 = 0; the triple point is invariant.A 0.5 molal aqueous solution of urea (a non-electrolyte) is prepared. If Kf of water is 1.86 K kg mol⁻¹, the depression in freezing point is:
Chapter 3: Solutions and Colligative Properties
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Answer: B. 0.93 K
ΔTf = Kf × m = 1.86 × 0.5 = 0.93 K (i = 1 for urea).A first-order reaction has rate constant k = 0.0693 min⁻¹. Its half-life is:
Chapter 6: Chemical Kinetics
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Answer: C. 10 min
For first order t½ = 0.693/k = 0.693/0.0693 = 10 min.According to the third law of thermodynamics, the entropy of a perfectly crystalline substance at absolute zero (0 K) is:
Chapter 4: Second and Third Law of Thermodynamics
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Answer: D. Zero
At 0 K a perfect crystal has only one possible arrangement (W = 1), so S = k ln 1 = 0.The oxidation state of iron in K₄[Fe(CN)₆] is:
Chapter 10: Coordination Compounds
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Answer: C. +2
4(+1) + x + 6(−1) = 0 gives x = +2.In complexometric titrations, EDTA (as EDTA⁴⁻) acts as a ligand that is:
Chapter 12: Titrimetric (Volumetric) Analysis
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Answer: D. Hexadentate
EDTA⁴⁻ binds a metal ion through two nitrogen atoms and four carboxylate oxygens: six donor sites.In paper or thin-layer chromatography, the Rf value is defined as:
Chapter 13: Chromatography
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Answer: B. Distance moved by solute ÷ distance moved by solvent front
Rf = distance travelled by the substance / distance travelled by the solvent front, so it is always less than 1.Which reagent is used in the Hinsberg test to distinguish primary, secondary and tertiary amines?
Chapter 14: Amines
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Answer: A. Benzenesulphonyl chloride
Hinsberg's reagent is C₆H₅SO₂Cl: the 1° amine sulphonamide dissolves in alkali, the 2° does not, and 3° amines do not react.According to the Stark–Einstein law of photochemical equivalence, each molecule taking part in the primary photochemical process absorbs:
Chapter 18: Photochemistry
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Answer: C. One quantum of radiation
The law states that one molecule is activated by absorbing exactly one quantum (photon), hν, in the primary step.
BSc Second Year (Sem 3 & 4): MCQ in other subjects
All questions are written by PadhaiNotes in our own words from the common syllabus of Maharashtra universities (NEP). Your own university's syllabus may differ a little.