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BSc Third Year (Sem 5 & 6) Physics – Daily Revision MCQ (English Medium)

📅 26 October 2026 · 10 questions · based on the Maharashtra university syllabus

This is the set for 26 October 2026. Solve today's MCQs →

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  1. According to Gauss's law, what is the total electric flux through a closed surface that encloses a net charge q in vacuum?

    Chapter 1: Electrostatics and Gauss's Law

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    Answer: B. q/ε₀
    Gauss's law: total flux through any closed surface = (net charge enclosed)/ε₀ = q/ε₀; it is zero only when no net charge is inside.

  2. A DC source has an internal (Thevenin) resistance of 4 Ω. For maximum power to be transferred to the load, the load resistance should be:

    Chapter 3: DC Circuits and Network Theorems

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    Answer: D. 4 Ω
    Maximum power transfer theorem: power in the load is maximum when R_L equals the source (Thevenin) resistance, here 4 Ω.

  3. At resonance in a series LCR circuit, the impedance of the circuit is:

    Chapter 4: Alternating Current Circuits

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    Answer: A. Minimum and equal to R
    At resonance X_L = X_C, so Z = √(R² + (X_L − X_C)²) = R, which is the minimum possible impedance.

  4. What is the maximum theoretical efficiency of a full-wave rectifier?

    Chapter 9: Semiconductor Diodes and Rectifiers

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    Answer: C. 81.2%
    η_max = 8/π² ≈ 0.812 for a full-wave rectifier, double the 40.6% of a half-wave rectifier.

  5. Which diode is used as a voltage-controlled variable capacitor?

    Chapter 10: Optoelectronic and Special Diodes: LED, Photodiode, Solar Cell, Varactor

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    Answer: B. Varactor diode
    A reverse-biased varactor's depletion-layer width, and hence its capacitance, changes with the applied reverse voltage.

  6. A transistor has a common-base current gain α = 0.98. What is its common-emitter current gain β?

    Chapter 11: Transistors

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    Answer: A. 49
    β = α/(1 − α) = 0.98/0.02 = 49.

  7. An op-amp inverting amplifier has Rf = 100 kΩ and Rin = 10 kΩ. What is its voltage gain?

    Chapter 12: Operational Amplifiers

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    Answer: D. −10
    Inverting amplifier gain A = −Rf/Rin = −100/10 = −10 (the minus sign shows a 180° phase shift).

  8. The de Broglie wavelength of a particle having momentum p is:

    Chapter 13: Origin of Quantum Mechanics

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    Answer: C. h/p
    de Broglie proposed that every moving particle has a wave associated with it, of wavelength λ = h/p.

  9. For a particle in a one-dimensional infinite potential box, what is the ratio E₂/E₁ of the second energy level to the first?

    Chapter 14: Schrödinger Equation

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    Answer: A. 4
    E_n = n²h²/(8mL²), so energy ∝ n²; E₂/E₁ = 2²/1² = 4.

  10. In a Raman spectrum, compared with the incident (Rayleigh) line, the Stokes lines appear at:

    Chapter 20: Raman Effect

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    Answer: D. Lower frequency (longer wavelength)
    In Stokes scattering the molecule takes energy from the photon, so the scattered light has lower frequency; anti-Stokes lines lie at higher frequency.

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All questions are written by PadhaiNotes in our own words from the common syllabus of Maharashtra universities (NEP). Your own university's syllabus may differ a little.