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Organic Chemistry-4 (NMR, Enolates and Natural Products) BCH5T09

RTMNU B.Sc Semester 5 · Chemistry · DSC (Major core) · 4 units · notes for every unit

UniversityRTMNU – Rashtrasant Tukadoji Maharaj Nagpur University, Nagpur
CourseB.Sc (Four Year UG Programme, NEP 2020) – Chemistry
SemesterSemester V
Paper codeBCH5T09
Paper titleOrganic Chemistry-4 (NMR, Enolates and Natural Products)
CategoryDSC (Major core)
CreditsTheory 2 credits (30 hours) + Practical 1 credit
MarksTheory marks not printed on the syllabus page
Syllabusas per official RTMNU NEP 2020 B.Sc syllabus for Sem V & VI (w.e.f. session 2026-27)

Unit topics below follow the official RTMNU syllabus. RTMNU official website · All RTMNU Chemistry papers

Units

  1. 1Unit I: NMR SpectroscopyNotes
  2. 2Unit II: Active Methylene CompoundsNotes
  3. 3Unit III: Lipids, Fats and OilsNotes
  4. 4Unit IV: PolymersNotes

RTMNU B.Sc Sem 5 · BCH5T09 · Unit I

Unit I: NMR Spectroscopy

Syllabus topics (RTMNU)

  • Basic principles
  • Concept of nuclear spin
  • Equivalent and non-equivalent protons
  • Reference compound TMS
  • Factors affecting chemical shift
  • Nuclear Magnetic Resonance (NMR) spectroscopy
  • Proton Magnetic Resonance spectroscopy
  • Nuclear shielding and deshielding
  • Chemical shift
  • Spin-spin splitting and Coupling constant
  • Areas of signals
  • Interpretation of NMR spectra of organic molecules and structure elucidation of simple organic molecules on the basis of NMR data such as ethyl bromide, ethanol, acetaldehyde, 1,2-dibromoethane, ethyl acetate, toluene, acetophenone, acetyl acetone

Basic Principles of NMR and Concept of Nuclear Spin

Nuclear Magnetic Resonance (NMR) spectroscopy is the study of the absorption of radio-frequency radiation by certain nuclei placed in a strong magnetic field. It tells us the number of different kinds of protons (or carbons), their chemical environment and their neighbours — the best tool for finding the structure of organic compounds.

Nuclear spin: nuclei with an odd number of protons or neutrons spin and have a spin quantum number I ≠ 0, e.g. 1H, 13C, 19F, 31P (all I = ½). 12C and 16O have I = 0 and are NMR-inactive. A spinning charged nucleus behaves like a tiny magnet.

In an external magnetic field (B0) a nucleus with spin I takes (2I + 1) orientations. A proton (I = ½) has two: α-spin (aligned with the field, lower energy) and β-spin (opposed, higher energy). The energy gap ΔE = hγB0/2π increases with field strength. When radio waves of exactly this energy (ν = γB0/2π, the resonance condition) are applied, the proton "flips" from α to β — this absorption is nuclear magnetic resonance. For protons, a field of 1.41 tesla needs 60 MHz and 2.35 tesla needs 100 MHz.

Proton Magnetic Resonance (PMR or 1H NMR) is NMR of hydrogen nuclei — the most common type. The spectrum is a plot of absorption (y-axis) against chemical shift δ in ppm (x-axis, decreasing from left to right).

Equivalent and Non-Equivalent Protons

Equivalent protons are protons in the same chemical environment; they absorb at the same position and give one signal. Non-equivalent protons give separate signals. So the number of signals = number of sets of equivalent protons. Examples: CH4, C6H6, CH3OCH3 — 1 signal each; CH3CH2Br — 2 signals; CH3CH2OH — 3 signals; (CH3)2CHCl — 2 signals.

Shielding, Deshielding, Chemical Shift and Reference Compound TMS

Electrons around a proton circulate in the applied field and create a small opposing field. This shielding means a higher applied field is needed for resonance — the signal moves upfield (right, low δ). When electron density around the proton is reduced (e.g. by an electronegative atom), the proton is deshielded and absorbs downfield (left, high δ).

Chemical shift is the position of a signal relative to a reference, expressed in parts per million (ppm):

δ (ppm) = [ν(sample) − ν(TMS)] ÷ ν(spectrometer, MHz) × 106 (with ν in Hz)
Example: a signal 220 Hz downfield from TMS on a 100 MHz instrument has δ = 220 ÷ 100 = 2.2 ppm. The same proton is 132 Hz away on a 60 MHz instrument, still δ 2.2 — δ does not depend on the instrument.

Tetramethylsilane (TMS), (CH3)4Si, is the reference (δ = 0) because: (1) its 12 protons are equivalent and give one sharp signal; (2) silicon is less electronegative than carbon, so its protons are highly shielded and appear upfield of almost all organic protons; (3) it is chemically inert; (4) volatile (b.p. 27 °C), easy to remove; (5) soluble in most organic solvents.

Factors Affecting Chemical Shift

  1. Electronegativity (inductive effect): electronegative atoms pull electrons away and deshield nearby protons: CH3F (δ 4.3) > CH3Cl (3.0) > CH3Br (2.7) > CH3I (2.2). The effect falls off with distance.
  2. Magnetic anisotropy (π-electron circulation): the ring current of benzene strongly deshields aromatic protons (δ 6.5–8); aldehyde proton δ 9–10; alkene protons δ 4.5–6. Acetylenic protons are shielded (δ 2–3) because they lie along the axis of the cylindrical π-cloud.
  3. Hydrogen bonding: H-bonded protons (OH, NH) are deshielded; their δ varies with concentration, solvent and temperature (alcohol OH δ 1–5; carboxylic acid OH δ 10–13).
  4. Hybridisation of the carbon bearing the proton, and van der Waals deshielding in crowded molecules.
Type of protonApproximate δ (ppm)
R–CH30.9
R–CH2–R1.3
CH3–C=O2.0–2.6
Ar–CH32.3
CH2–X (Br, Cl), CH2–O3.3–4.2
Alkene C=C–H4.5–6.0
Aromatic Ar–H6.5–8.0
Aldehyde –CHO9–10
Carboxylic acid –COOH10–13

Spin–Spin Splitting, Coupling Constant and Area of Signals

Spin–spin splitting: a proton's signal is split by protons on adjacent carbons (usually up to three bonds away), because their spins add to or subtract from the field it feels. (n + 1) rule: a signal is split into (n + 1) peaks by n equivalent neighbouring protons: 0 → singlet, 1 → doublet (1:1), 2 → triplet (1:2:1), 3 → quartet (1:3:3:1), 4 → quintet. Relative intensities follow Pascal's triangle. Equivalent protons do not split each other; protons on O–H often do not split because of fast exchange.

Coupling constant (J): the distance between adjacent peaks of a multiplet, in hertz. It does not depend on the applied field. Protons that split each other have the same J (e.g. about 7 Hz for CH3–CH2), which helps to match signals.

Area of signals (integration): the area under each signal is proportional to the number of protons producing it. The integration curve (step heights) gives the proton ratio, e.g. 3 : 2 in ethyl bromide.

Interpretation of NMR Spectra of Simple Molecules

CompoundSignals: δ (ppm), multiplicity, protons
Ethyl bromide CH3CH2Br2 signals: 1.7 triplet (3H, CH3); 3.4 quartet (2H, CH2Br); ratio 3:2
Ethanol CH3CH2OH3 signals: 1.2 triplet (3H); 3.7 quartet (2H, CH2O); about 2.6 singlet (1H, OH, position variable). In very pure ethanol OH appears as a triplet and CH2 as a multiplet.
Acetaldehyde CH3CHO2 signals: 2.2 doublet (3H, CH3); 9.8 quartet (1H, CHO); ratio 3:1
1,2-Dibromoethane BrCH2CH2Br1 signal: 3.6 singlet (4H) — all protons equivalent, so no splitting
Ethyl acetate CH3COOCH2CH33 signals: 2.0 singlet (3H, CH3CO); 4.1 quartet (2H, OCH2); 1.25 triplet (3H, CH3)
Toluene C6H5CH32 signals: 2.3 singlet (3H, Ar–CH3); about 7.2 (5H, aromatic, near-singlet/multiplet)
Acetophenone C6H5COCH32.6 singlet (3H, COCH3); 7.4–7.6 multiplet (3H, meta + para) and about 7.95 multiplet (2H, ortho, deshielded by C=O)
Acetylacetone CH3COCH2COCH3 ⇌ enolExists mainly as the enol (H-bonded). Enol: about 15.5 broad singlet (1H, enolic OH), 5.5 singlet (1H, =CH–), 2.0 singlet (6H, 2 CH3). Keto form: 3.6 singlet (2H, CH2), 2.2 singlet (6H). Both sets appear because tautomerism is slow on the NMR time scale.

Structure elucidation example: A compound C2H4O shows a doublet at δ 2.2 (3H) and a quartet at δ 9.8 (1H). The δ 9.8 signal shows –CHO; the doublet/quartet pair shows CH3 next to CH. Structure: CH3CHO (acetaldehyde).

Exam tip: For structure problems, (1) find degrees of unsaturation from the formula, (2) count signals, (3) use δ to identify groups, (4) use integration for proton counts, (5) use the n + 1 rule to join neighbouring groups.

Likely exam questions

  1. (Long, 8 marks) Explain the basic principle of NMR spectroscopy. What is chemical shift? Discuss the factors affecting chemical shift.
  2. (Long, 8 marks) What is spin–spin splitting? Explain the (n + 1) rule and coupling constant. Interpret the PMR spectra of ethyl bromide and ethyl acetate.
  3. (Short, 4 marks) Why is TMS used as a reference compound in NMR?
  4. (Short, 4 marks) Distinguish between shielding and deshielding of protons.
  5. (Short, 4 marks) Predict the number of signals, their multiplicity and relative areas in the PMR spectrum of acetaldehyde.

RTMNU B.Sc Sem 5 · BCH5T09 · Unit II

Unit II: Active Methylene Compounds

Syllabus topics (RTMNU)

  • Concept of active methylene group
  • Explanation of acidity and reactivity of methylene hydrogen atoms
  • General mechanism of enolate formation and its nucleophilic character
  • Factors affecting acidity
  • Malonic ester: Preparation and synthetic applications in preparation of monocarboxylic acids (Acetic acid, n-butyric acid, n-valeric acid, Dimethyl acetic acid, 2-methyl butanoic acid), dicarboxylic acids (Succinic acid, Adipic acid), α,β-unsaturated acids (Crotonic acid, Cinnamic acid), β-keto acids (Acetoacetic acid) and heterocyclic compounds (Barbituric acid)
  • Acetoacetic ester: Synthesis by Claisen condensation reactions
  • Keto-enol tautomerism of acetoacetic ester
  • Application of acetoacetic ester in preparation of monocarboxylic acids, dicarboxylic acids, α,β-unsaturated acids, ketones (Acetone, Methyl propyl ketone), diketones (Acetyl acetone, Acetonyl acetone) and heterocyclic compounds (4-methyl uracil, Methyl iso-oxazolone)

Concept of Active Methylene Group, Acidity and Reactivity

An active methylene group is a –CH2– group placed between two electron-withdrawing groups (C=O, COOR, CN, NO2). Its hydrogens are unusually acidic and the carbon is very reactive. Examples: diethyl malonate CH2(COOC2H5)2 (pKa ≈ 13), ethyl acetoacetate CH3COCH2COOC2H5 (pKa ≈ 11), acetylacetone CH3COCH2COCH3 (pKa ≈ 9), ethyl cyanoacetate.

Why acidic: (1) both groups withdraw electrons by −I and −M effects and weaken the C–H bond; (2) the carbanion formed after losing H+ is resonance-stabilised — the negative charge spreads over the carbon and both oxygens (an enolate ion).

General mechanism of enolate formation: a base such as sodium ethoxide removes a proton:

CH2(COOEt)2 + C2H5O−Na+ → Na+ [−CH(COOEt)2 ↔ enolate forms with O−] + C2H5OH
Enolate (nucleophile) + R–X → R–CH(COOEt)2 + X−  (SN2 alkylation)

Nucleophilic character: the enolate carbon attacks alkyl halides (alkylation), acyl chlorides (acylation), aldehydes (Knoevenagel) and halogens. A second alkylation is possible because one acidic H remains.

Factors affecting acidity: number and strength of electron-withdrawing groups (ketone C=O > ester C=O, so EAA is more acidic than malonic ester); extent of resonance stabilisation of the anion; alkyl substituents on the carbon decrease acidity (+I effect); solvent and base strength.

Malonic Ester: Preparation

Diethyl malonate is prepared from chloroacetic acid:

ClCH2COOH + NaOH (or Na2CO3) → ClCH2COONa
ClCH2COONa + KCN → NC–CH2COONa + KCl
NC–CH2COONa + 2 C2H5OH + H2SO4/HCl (heat) → CH2(COOC2H5)2 (diethyl malonate)  [–CN hydrolysed and both acids esterified]

Key idea: alkylate the sodio-malonic ester, then hydrolyse to the substituted malonic acid, which loses CO2 on heating (a gem-dicarboxylic acid decarboxylates easily):

R–CH(COOEt)2 → (KOH, then H3O+) → R–CH(COOH)2 → (heat, −CO2) → R–CH2–COOH

Synthetic Applications of Malonic Ester

ProductRoute
Acetic acidCH2(COOEt)2 → hydrolysis → CH2(COOH)2 → heat, −CO2 → CH3COOH
n-Butyric acidNa-malonic ester + C2H5Br → C2H5CH(COOEt)2 → hydrolysis, −CO2 → CH3CH2CH2COOH
n-Valeric acidNa-malonic ester + n-C3H7Br → n-C3H7CH(COOEt)2 → hydrolysis, −CO2 → CH3(CH2)3COOH
Dimethylacetic (isobutyric) acidTwo methylations: (i) NaOEt, CH3I (ii) NaOEt, CH3I → (CH3)2C(COOEt)2 → hydrolysis, −CO2 → (CH3)2CHCOOH
2-Methylbutanoic acid(i) NaOEt, CH3I (ii) NaOEt, C2H5Br → CH3(C2H5)C(COOEt)2 → hydrolysis, −CO2 → CH3CH2CH(CH3)COOH
Succinic acidNa-malonic ester + ClCH2COOEt → (EtOOC)2CH–CH2COOEt → hydrolysis, −CO2 → HOOC–CH2CH2–COOH. (Or: 2 Na-malonic ester + I2 → (EtOOC)2CH–CH(COOEt)2 → hydrolysis, −2CO2.)
Adipic acid2 Na-malonic ester + BrCH2CH2Br → (EtOOC)2CH–CH2CH2–CH(COOEt)2 → hydrolysis, −2CO2 → HOOC–(CH2)4–COOH
Crotonic acidKnoevenagel: CH3CHO + CH2(COOH)2 (pyridine) → CH3CH=C(COOH)2 → −CO2 → CH3CH=CHCOOH
Cinnamic acidC6H5CHO + CH2(COOH)2 (pyridine/piperidine) → C6H5CH=C(COOH)2 → −CO2 → C6H5CH=CHCOOH
Acetoacetic acid (β-keto acid)Na-malonic ester + CH3COCl → CH3CO–CH(COOEt)2 → mild hydrolysis, −CO2 → CH3COCH2COOH
Barbituric acidCH2(COOEt)2 + H2N–CO–NH2 (urea), NaOEt → cyclic malonylurea (barbituric acid) + 2 C2H5OH

Acetoacetic Ester: Synthesis by Claisen Condensation

Ethyl acetoacetate (EAA) is made by the Claisen condensation of two molecules of ethyl acetate in the presence of sodium ethoxide:

2 CH3COOC2H5 → (C2H5ONa) → CH3COCH2COOC2H5 + C2H5OH

Mechanism: (1) ethoxide removes an α-H from ethyl acetate → enolate −CH2COOEt; (2) the enolate attacks the carbonyl carbon of a second ethyl acetate → tetrahedral intermediate; (3) it expels ethoxide → EAA; (4) EAA (more acidic) is deprotonated by ethoxide to its stable sodio-enolate — this drives the reaction; (5) acidification gives EAA.

Keto–Enol Tautomerism of Acetoacetic Ester

EAA exists as an equilibrium mixture of two forms (about 92% keto and 8% enol at room temperature):

CH3–CO–CH2–COOC2H5 (keto) ⇌ CH3–C(OH)=CH–COOC2H5 (enol)

Evidence for keto form: forms a cyanohydrin with HCN, bisulphite compound with NaHSO3, hydrazone with phenylhydrazine (C=O group). Evidence for enol form: decolourises bromine water (C=C), gives a violet/red colour with neutral FeCl3 (enolic –OH), liberates H2 with sodium, reacts with acetyl chloride. The enol is stabilised by conjugation and an intramolecular hydrogen bond (six-membered chelate).

Synthetic Applications of Acetoacetic Ester

Sodio-EAA is alkylated or acylated, then hydrolysed in one of two ways:

Ketonic hydrolysis (dilute KOH or dilute acid, then heat): CH3CO–CHR–COOEt → CH3CO–CH2R + CO2 + C2H5OH (gives ketones)
Acid hydrolysis (concentrated alcoholic KOH): CH3CO–CHR–COOEt → CH3COOH + R–CH2–COOH (gives acids)
ProductRoute
Acetic acidEAA → acid hydrolysis → 2 CH3COOH
n-Butyric acidNa-EAA + C2H5I → CH3COCH(C2H5)COOEt → acid hydrolysis → CH3CH2CH2COOH + CH3COOH
n-Valeric acidNa-EAA + n-C3H7I → acid hydrolysis → CH3(CH2)3COOH + CH3COOH
Dimethylacetic acidMethylate twice → CH3COC(CH3)2COOEt → acid hydrolysis → (CH3)2CHCOOH + CH3COOH
2-Methylbutanoic acidMethylate, then ethylate → CH3COC(CH3)(C2H5)COOEt → acid hydrolysis → CH3CH2CH(CH3)COOH + CH3COOH
Succinic acidNa-EAA + ClCH2COOEt → CH3COCH(CH2COOEt)COOEt → acid hydrolysis → HOOCCH2CH2COOH + CH3COOH
Adipic acid2 Na-EAA + BrCH2CH2Br → CH3COCH(COOEt)CH2CH2CH(COOEt)COCH3 → acid hydrolysis → HOOC(CH2)4COOH + 2 CH3COOH
Crotonic acidEAA → reduction (Na/Hg or NaBH4) → CH3CH(OH)CH2COOEt → hydrolysis and dehydration → CH3CH=CHCOOH
Cinnamic acidEAA + C6H5CHO (piperidine) → C6H5CH=C(COCH3)COOEt → acid hydrolysis → C6H5CH=CHCOOH + CH3COOH
AcetoneEAA → ketonic hydrolysis → CH3COCH3 + CO2 + C2H5OH
Methyl propyl ketone (pentan-2-one)Na-EAA + C2H5I → CH3COCH(C2H5)COOEt → ketonic hydrolysis → CH3COCH2CH2CH3
AcetylacetoneNa-EAA + CH3COCl → CH3COCH(COCH3)COOEt → ketonic hydrolysis → CH3COCH2COCH3
Acetonylacetone (hexane-2,5-dione)2 Na-EAA + I2 → CH3COCH(COOEt)–CH(COOEt)COCH3 → ketonic hydrolysis → CH3COCH2CH2COCH3
4-MethyluracilEAA + urea (heat, acid catalyst) → condensation and cyclisation → 4(6)-methyluracil + C2H5OH + H2O
Methyl isoxazolone (3-methylisoxazol-5-one)EAA + NH2OH → oxime of EAA → cyclisation with loss of C2H5OH → 3-methyl-5-isoxazolone
Exam tip: In every synthesis write all three steps — (1) formation of the sodio derivative with NaOEt, (2) alkylation/acylation with the correct halide, (3) the right hydrolysis (ketonic for ketones, acid for acids) with decarboxylation.

Likely exam questions

  1. (Long, 8 marks) What is an active methylene group? Explain the acidity of its hydrogens. How is malonic ester prepared? Give its use in the synthesis of n-butyric acid, adipic acid and barbituric acid.
  2. (Long, 8 marks) Describe the synthesis of acetoacetic ester by Claisen condensation with mechanism. Explain its keto–enol tautomerism with evidence.
  3. (Short, 4 marks) How will you prepare acetylacetone from acetoacetic ester?
  4. (Short, 4 marks) Distinguish between ketonic hydrolysis and acid hydrolysis of acetoacetic ester.
  5. (Short, 4 marks) Synthesise cinnamic acid from malonic ester (or malonic acid).

RTMNU B.Sc Sem 5 · BCH5T09 · Unit III

Unit III: Lipids, Fats and Oils

Syllabus topics (RTMNU)

  • Introduction to lipids, classification
  • Oils and fats: classification of oils
  • Common fatty acids present in oils and fats
  • Omega fatty acids
  • Trans fats
  • Hydrogenation
  • Saponification value, Iodine number
  • Biological importance of triglycerides, phospholipids, glycolipids, and steroids (cholesterol)
  • Natural fats, edible and industrial oils of vegetable origin
  • Glycerides
  • Hydrogenation of unsaturated oils
  • Definition of Saponification value, Iodine value, Acid value
  • Soaps - different types of soaps
  • Cleansing action of soap
  • Synthetic detergents
  • Alkyl and aryl sulfonates

Introduction to Lipids and Classification

Lipids are naturally occurring organic compounds that are insoluble in water but soluble in non-polar solvents (ether, chloroform, benzene); they are esters of fatty acids or substances related to them. Examples: fats, oils, waxes, phospholipids, steroids.

Classification (Bloor):

  1. Simple lipids: esters of fatty acids with alcohols — (a) fats and oils (triglycerides: esters of glycerol); (b) waxes (esters of long-chain alcohols, e.g. beeswax).
  2. Compound (complex) lipids: contain other groups besides fatty acid and alcohol — phospholipids (lecithin, cephalin), glycolipids (cerebrosides), lipoproteins.
  3. Derived lipids: obtained by hydrolysis of the above — fatty acids, glycerol, steroids (cholesterol), fat-soluble vitamins.

Oils and Fats: Classification, Common Fatty Acids, Omega Fatty Acids and Trans Fats

Fats and oils are triglycerides (glycerides) — triesters of glycerol with fatty acids. Fats are solid at room temperature (rich in saturated acids, e.g. ghee, lard); oils are liquid (rich in unsaturated acids, e.g. groundnut, sunflower).

CH2OH–CHOH–CH2OH + 3 RCOOH → CH2(OCOR)–CH(OCOR)–CH2(OCOR) (triglyceride) + 3 H2O

Classification of oils: (1) by source — vegetable (groundnut, coconut, mustard) and animal (fish oil, lard); (2) by use — edible and industrial (linseed, castor); (3) by drying property — drying oils (iodine value > 130, e.g. linseed, tung — form a hard film; used in paints), semi-drying oils (100–130, e.g. cottonseed, soybean), non-drying oils (< 100, e.g. coconut, olive, groundnut).

Fatty acidFormulaType
LauricC11H23COOH (C12)Saturated (coconut)
MyristicC13H27COOH (C14)Saturated
PalmiticC15H31COOH (C16)Saturated (palm oil)
StearicC17H35COOH (C18)Saturated
OleicC17H33COOH (C18, one C=C at C-9)Mono-unsaturated, ω-9
LinoleicC17H31COOH (C18, two C=C)Poly-unsaturated, ω-6
α-LinolenicC17H29COOH (C18, three C=C)Poly-unsaturated, ω-3

Omega fatty acids: named by the position of the first double bond counted from the methyl (ω) end. ω-3: α-linolenic acid (flaxseed/alsi), EPA and DHA (fish oil) — good for heart and brain. ω-6: linoleic and arachidonic acids (sunflower, safflower oils). Linoleic and linolenic acids are essential fatty acids — the body cannot make them.

Trans fats: unsaturated fats with a trans C=C (natural fats are mostly cis). They form mainly during partial hydrogenation (vanaspati) and repeated frying. They raise "bad" LDL cholesterol and lower "good" HDL, increasing heart disease risk; FSSAI limits trans fat in oils and fats to 2% (check latest).

Hydrogenation of Unsaturated Oils

Liquid oils are converted into semi-solid fats by adding hydrogen to C=C bonds in the presence of finely divided nickel at about 150–200 °C and a few atmospheres pressure (hardening of oils). Product: vanaspati ghee; it raises melting point and keeping quality.

Triolein (liquid) + 3 H2 → (Ni, ≈ 180 °C) → Tristearin (solid)

Saponification Value, Iodine Value and Acid Value

  1. Saponification value (SV): the number of milligrams of KOH required to completely saponify 1 g of a fat or oil. It is inversely proportional to the average molar mass of the glycerides: short-chain fats (coconut, about 250–260) have high SV; most oils 185–200. It detects adulteration.
  2. Iodine value (IV): the number of grams of iodine absorbed by 100 g of fat or oil. It measures unsaturation; determined by Wijs method (ICl in acetic acid). Higher IV = more unsaturated = more drying.
  3. Acid value (AV): the number of milligrams of KOH required to neutralise the free fatty acids in 1 g of fat or oil. A high value shows rancidity (hydrolysis) — poor quality.

Worked numericals:

(1) SV of tristearin (C57H110O6, M = 891.5 g/mol). 1 mol needs 3 mol KOH = 3 × 56.1 = 168.3 g. SV = 168.3 × 1000 ÷ 891.5 = 188.8 mg KOH/g.

(2) IV of triolein (C57H104O6, M = 885.4 g/mol, three C=C). It absorbs 3 I2 = 3 × 253.8 = 761.4 g per mol. IV = 761.4 × 100 ÷ 885.4 = 86.0.

(3) Acid value: 2.0 g of oil needs 1.5 mL of 0.1 N KOH. KOH used = 1.5 × 0.1 × 56.1 = 8.415 mg. AV = 8.415 ÷ 2.0 = 4.21 mg KOH/g.

Biological Importance of Triglycerides, Phospholipids, Glycolipids and Cholesterol

  1. Triglycerides: main energy store (about 9 kcal/g, more than carbohydrates); stored in adipose tissue; insulate the body and cushion organs; carry fat-soluble vitamins A, D, E, K.
  2. Phospholipids (lecithin, cephalin): have a polar head and two non-polar tails; form the lipid bilayer of cell membranes; lecithin acts as an emulsifier; part of lipoproteins and lung surfactant.
  3. Glycolipids (cerebrosides, gangliosides): found in cell membranes, especially the myelin sheath of nerves; act in cell recognition and as receptors.
  4. Cholesterol (a steroid, C27H45OH): controls membrane fluidity; precursor of steroid hormones (cortisol, testosterone, oestrogen), bile acids and vitamin D. Excess in blood leads to atherosclerosis.

Natural Fats and Oils: Edible and Industrial Oils, Glycerides

Edible vegetable oils: groundnut, mustard, soybean, sunflower, coconut, sesame (til), cottonseed, rice bran, palm oil. Industrial oils: linseed (paints, varnishes, linoleum), castor (lubricants, brake fluid, medicine), tung (varnishes), neem (soaps, pesticides). Natural fats are mixtures of mixed glycerides (different fatty acids on one glycerol); simple glycerides have the same acid in all three positions (e.g. tristearin).

Soaps: Types and Cleansing Action

Soaps are sodium or potassium salts of higher fatty acids, made by saponification — boiling fat or oil with NaOH or KOH:

Triglyceride + 3 NaOH → 3 RCOONa (soap) + glycerol

Types: hard soaps (sodium salts; laundry and toilet soaps); soft soaps (potassium salts; shaving creams, liquid soaps); toilet soaps (pure, with perfume and colour); transparent soaps (dissolved in alcohol/glycerol); medicated soaps (with antiseptics like neem or carbolic acid); metallic soaps (Ca, Al salts — used in greases).

Cleansing action: a soap molecule has a long non-polar hydrocarbon tail (hydrophobic, dissolves in grease) and a polar –COO− head (hydrophilic, dissolves in water). In water, soap molecules form micelles: tails point inward into the oily dirt, heads face the water. The grease is broken into tiny droplets surrounded by negative charges, which repel each other and form a stable emulsion that is washed away. Soap also lowers surface tension so water wets the cloth better.

Limitation: in hard water, Ca2+ and Mg2+ form insoluble scum: 2 RCOONa + Ca2+ → (RCOO)2Ca↓ + 2 Na+. Soap is wasted.

Synthetic Detergents: Alkyl and Aryl Sulphonates

Synthetic detergents are cleansing agents that work like soap but are salts of sulphonic acids or alkyl hydrogen sulphates; their calcium and magnesium salts are soluble, so they work even in hard water and acidic solution.

  1. Alkyl sulphates / sulphonates (anionic): e.g. sodium lauryl sulphate C12H25OSO3Na, made from lauryl alcohol + H2SO4, then NaOH; used in shampoos and toothpastes. Alkane sulphonates R–SO3Na also belong here.
  2. Aryl (alkylbenzene) sulphonates (anionic): e.g. sodium dodecylbenzene sulphonate — dodecylbenzene is sulphonated with conc. H2SO4 and neutralised with NaOH; the main ingredient of washing powders.
  3. Cationic detergents: quaternary ammonium salts, e.g. cetyltrimethylammonium bromide — germicidal, in hair conditioners. Non-ionic: polyethylene glycol esters — in liquid dishwash.
Remember: branched alkylbenzene sulphonates are not biodegradable and cause foam in rivers; linear alkylbenzene sulphonates (LAS) are biodegradable and are used today.

Likely exam questions

  1. (Long, 8 marks) Define saponification value, iodine value and acid value and give their significance. Calculate the saponification value of tristearin (M = 891.5).
  2. (Long, 8 marks) What are soaps? Describe the types of soaps and explain the cleansing action of soap. How do synthetic detergents differ from soaps?
  3. (Short, 4 marks) What are omega fatty acids? Give examples.
  4. (Short, 4 marks) What is hydrogenation of oils? Why are trans fats harmful?
  5. (Short, 4 marks) Write the biological importance of phospholipids and cholesterol.

RTMNU B.Sc Sem 5 · BCH5T09 · Unit IV

Unit IV: Polymers

Syllabus topics (RTMNU)

  • Definition of polymers
  • Classification of polymers on the basis of nature, thermal behaviour, and structure
  • Reaction mechanism of addition or chain growth polymerisation, free radical
  • Ionic addition polymerisation
  • Condensation or step growth polymerisation
  • Preparation and uses of Polydienes (Buna-S)
  • Polyacrylates (Polyacrylonitrile)
  • Polyhalo-olefins (PVC)
  • Polyesters (terylene)
  • Polyamides (Nylon 66, Nylon 6)
  • Phenol-formaldehyde resins (Bakelite)
  • Urea-formaldehyde resins

Definition of Polymers

Polymers are very large molecules (macromolecules) of high molecular mass made by joining many small repeating units called monomers through covalent bonds. The process is called polymerisation. Example: n CH2=CH2 → –(CH2–CH2)n– (polythene). The number of repeating units n is the degree of polymerisation.

Classification of Polymers

1. On the basis of nature (source):

  • Natural: from plants and animals — starch, cellulose, proteins, natural rubber.
  • Semi-synthetic: chemically modified natural polymers — cellulose acetate (rayon), vulcanised rubber.
  • Synthetic: man-made — polythene, PVC, nylon, terylene, Bakelite.

2. On the basis of thermal behaviour:

  • Thermoplastics: soften on heating and harden on cooling repeatedly; linear or slightly branched chains with weak intermolecular forces; can be remoulded and recycled — polythene, PVC, polystyrene.
  • Thermosetting polymers: on heating they become permanently hard due to extensive cross-linking; cannot be remoulded — Bakelite, urea-formaldehyde resin.

3. On the basis of structure:

  • Linear polymers: long straight chains — high-density polythene, PVC.
  • Branched-chain polymers: linear chains with side branches — low-density polythene.
  • Cross-linked (network) polymers: chains joined by strong covalent bonds in three dimensions — Bakelite, melamine.

Also: by monomers — homopolymers (one monomer, e.g. PVC) and copolymers (two monomers, e.g. Buna-S, nylon 66); by mode of polymerisation — addition and condensation.

Addition (Chain-Growth) Polymerisation: Free Radical Mechanism

In addition polymerisation unsaturated monomers (alkenes, dienes) add to each other repeatedly without loss of any small molecule; the polymer has the same empirical formula as the monomer. It takes place through a chain reaction with three steps. Initiators: benzoyl peroxide, acetyl peroxide, AIBN.

Initiation: (C6H5COO)2 → 2 C6H5COO• → 2 C6H5• + 2 CO2;  C6H5• + CH2=CH2 → C6H5–CH2–CH2•
Propagation: C6H5–CH2CH2• + n CH2=CH2 → C6H5–(CH2CH2)n–CH2CH2•
Termination: two growing radicals combine (coupling), or one takes an H atom from the other (disproportionation), giving the dead polymer.

Ionic Addition Polymerisation

  1. Cationic polymerisation: initiated by a Lewis acid with a trace of water (BF3/H2O, AlCl3) or a strong protic acid. H+ adds to the alkene to give a carbocation, which adds more monomer. Works for monomers with electron-releasing groups — isobutylene (butyl rubber), vinyl ethers, styrene. Termination by loss of a proton or combining with the counter-ion.
  2. Anionic polymerisation: initiated by strong bases/nucleophiles — n-butyllithium, NaNH2, sodium naphthalide. The anion adds to the alkene to form a carbanion that grows. Works for monomers with electron-withdrawing groups — acrylonitrile, methyl methacrylate, styrene. Often there is no natural termination ("living polymers") until water or acid is added.

Condensation (Step-Growth) Polymerisation

In condensation polymerisation, monomers having two (or more) functional groups react step by step with the loss of small molecules such as H2O, HCl or CH3OH. Any two species (monomer, dimer, oligomer) can react; molecular mass rises slowly. Examples: nylon 66, terylene, Bakelite.

Addition (chain-growth)Condensation (step-growth)
Monomers are unsaturatedMonomers have two functional groups
No by-product is lostSmall molecule (H2O, HCl) is lost
Fast chain reaction via radicals/ionsSlow step-wise reaction
High polymer forms earlyMolecular mass builds up gradually
e.g. PVC, PAN, Buna-Se.g. nylon 66, terylene, Bakelite

Preparation and Uses of Important Polymers

1. Buna-S (polydiene; styrene–butadiene rubber, SBR): copolymer of 1,3-butadiene (about 75%) and styrene (about 25%), made by free-radical emulsion polymerisation (earlier with sodium as catalyst, hence "Bu-Na").

n CH2=CH–CH=CH2 + n C6H5CH=CH2 → –[CH2–CH=CH–CH2–CH2–CH(C6H5)]n–

Uses: automobile tyres, footwear soles, cable insulation, conveyor belts.

2. Polyacrylonitrile, PAN (polyacrylate): addition polymerisation of acrylonitrile with a peroxide catalyst.

n CH2=CH–CN → –(CH2–CH(CN))n–

Uses: acrylic fibres (Orlon, Acrilan) as a wool substitute — sweaters, blankets; precursor of carbon fibre.

3. Polyvinyl chloride, PVC (polyhalo-olefin): free-radical polymerisation of vinyl chloride with a peroxide.

n CH2=CHCl → –(CH2–CHCl)n–

Uses: water pipes, raincoats, handbags, floor tiles, electric cable insulation, vinyl sheets.

4. Terylene / Dacron (polyester, PET): condensation of ethylene glycol with terephthalic acid (or dimethyl terephthalate) at about 420–460 K with a catalyst (zinc acetate–antimony trioxide), with loss of water (or methanol).

n HO–CH2CH2–OH + n HOOC–C6H4–COOH (para) → –[O–CH2CH2–O–CO–C6H4–CO]n– + 2n H2O

Uses: crease-resistant fabrics, terycot and terywool blends, sails, seat belts, PET bottles, films.

5. Nylon 66 (polyamide): condensation of hexamethylenediamine (6 C) and adipic acid (6 C). They first form "nylon salt", which is heated at about 553 K under nitrogen.

n H2N–(CH2)6–NH2 + n HOOC–(CH2)4–COOH → –[NH–(CH2)6–NH–CO–(CH2)4–CO]n– + 2n H2O

Uses: textile fibres, stockings, ropes, fishing nets, tyre cords, brush bristles, gears.

6. Nylon 6 (polyamide): made by heating caprolactam with a little water at about 533–543 K; the ring opens (to 6-aminohexanoic acid) and polymerises.

n (CH2)5–CO–NH (caprolactam ring) → (H2O, heat) → –[NH–(CH2)5–CO]n–

Uses: tyre cords, fabrics, ropes, mountaineering ropes.

7. Phenol–formaldehyde resin (Bakelite): phenol reacts with formaldehyde (acid or base catalyst) to form o- and p-hydroxymethylphenols, which condense (losing water) through –CH2– bridges. A linear product, novolac, forms first; on heating with more formaldehyde (hexamethylenetetramine), it becomes a hard, infusible, three-dimensional cross-linked Bakelite.

Uses: electrical switches, plugs, handles of cookware, telephone cases, combs, varnish; novolac in paints.

8. Urea–formaldehyde resin: urea condenses with formaldehyde (mild acid or base) to form mono- and dimethylol urea, which further condense with loss of water to a cross-linked thermosetting resin.

H2N–CO–NH2 + HCHO → H2N–CO–NH–CH2OH (methylol urea) → (−H2O, heat) → –[NH–CO–NH–CH2]n– (cross-linked on curing)

Uses: adhesives for plywood and particle board, laminates, electrical fittings, buttons, unbreakable cups and decorative articles.

Exam tip: For each polymer write — monomer(s) with structure, type of polymerisation, catalyst/conditions, repeating unit, and 3–4 uses. Nylon 66 is so named because both monomers have 6 carbon atoms.

Likely exam questions

  1. (Long, 8 marks) Explain the free-radical mechanism of addition polymerisation. Compare addition and condensation polymerisation.
  2. (Long, 8 marks) Give the preparation and uses of nylon 66, terylene and Bakelite.
  3. (Short, 4 marks) Distinguish between thermoplastic and thermosetting polymers.
  4. (Short, 4 marks) How is Buna-S prepared? Give its uses.
  5. (Short, 4 marks) What is anionic polymerisation? Give one example.