Class 11 Mathematics and Statistics (Commerce) Part 1 – Daily Revision MCQ (English Medium)
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If n(A) = 3 and n(B) = 4, how many ordered pairs are there in A × B?
Chapter 1: Sets and Relations
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Answer: B. 12
n(A × B) = n(A) × n(B) = 3 × 4 = 12, since each element of A pairs with each element of B.How many elements does the power set of A = {1, 2, 3} have?
Chapter 1: Sets and Relations
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Answer: D. 8
The power set lists all subsets: ∅, {1}, {2}, {3}, {1,2}, {1,3}, {2,3}, {1,2,3}, which is 8 = 2³.If f(x) = 2x + 1 and g(x) = x², what is (f∘g)(3)?
Chapter 2: Functions
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Answer: A. 19
(f∘g)(3) = f(g(3)) = f(9) = 2 × 9 + 1 = 19. (49 would be (g∘f)(3).)What is the value of i³⁵?
Chapter 3: Complex Numbers
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Answer: C. −i
35 = 4 × 8 + 3, and i⁴ = 1, so i³⁵ = i³ = −i.What is the 6th term of the G.P. 3, 6, 12, 24, …?
Chapter 4: Sequences and Series
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Answer: B. 96
a = 3, r = 2, so t₆ = ar⁵ = 3 × 32 = 96.What is the slope of the line passing through the points A(1, 2) and B(4, 11)?
Chapter 5: Locus and Straight Line
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Answer: D. 3
Slope = (y₂ − y₁)/(x₂ − x₁) = (11 − 2)/(4 − 1) = 9/3 = 3.What is the value of the determinant with rows (2, 0, 0), (7, 3, 0) and (1, 5, 5)?
Chapter 6: Determinants
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Answer: A. 30
All entries above the diagonal are 0, so the value is the product of the diagonal entries: 2 × 3 × 5 = 30.Find lim (x→3) (x² − 9)/(x − 3).
Chapter 7: Limits
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Answer: C. 6
x² − 9 = (x − 3)(x + 3). Cancelling (x − 3) leaves x + 3, which is 6 at x = 3.f(x) = (x² − 4)/(x − 2) for x ≠ 2, and f(2) = k. For f to be continuous at x = 2, what must k be?
Chapter 8: Continuity
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Answer: D. 4
lim (x→2) f(x) = lim (x + 2) = 4, and continuity needs f(2) = this limit, so k = 4.If f(x) = x³ + 2x, what is f′(2)?
Chapter 9: Differentiation
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Answer: B. 14
f′(x) = 3x² + 2, so f′(2) = 3 × 4 + 2 = 14.
Class 11: MCQ in other subjects
All questions are written by PadhaiNotes in our own words from the chapters of the official Maharashtra State Board Balbharati textbook (ebalbharati.in). Each question shows its chapter.