Class 11 Chemistry – Daily Revision MCQ (English Medium)
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Who stated the law of definite proportion?
Chapter 1: Some Basic Concepts of Chemistry
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Answer: B. Joseph Proust
Joseph Proust stated that a given compound always contains the same elements in exactly the same proportion by weight, whatever its source.How many significant figures are there in the measurement 0.04050 g?
Chapter 2: Introduction to Analytical Chemistry
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Answer: C. 4
Zeros before the first non-zero digit are not significant; the zero between 4 and 5 and the final zero after the decimal point are significant: 4, 0, 5, 0 = 4.In paper chromatography, what acts as the stationary phase?
Chapter 3: Some Analytical Techniques
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Answer: A. Water trapped in the fibres of the paper
Paper chromatography is partition chromatography: the water held in the paper fibres is the stationary liquid phase and the solvent is the mobile phase.How many orbitals are present in a d subshell?
Chapter 4: Structure of Atom
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Answer: D. 5
A d subshell has five orbitals: dxy, dyz, dxz, dx²−y² and dz².Alkali metals dissolve in liquid ammonia to give a deep blue solution. What is responsible for this blue colour?
Chapter 8: Elements of Group 1 and 2
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Answer: A. Ammoniated electrons
The deep blue colour of alkali metals in liquid ammonia is due to the ammoniated (solvated) electron.What is the general valence shell electronic configuration of the Group 14 (carbon family) elements?
Chapter 9: Elements of Group 13, 14 and 15
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Answer: B. ns² np²
Group 14 elements have four valence electrons, two in the s and two in the p orbital: ns² np² (e.g. C: [He]2s²2p²).At constant pressure, a fixed mass of gas occupies 2.0 L at 300 K. What will its volume be at 450 K?
Chapter 10: States of Matter
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Answer: C. 3.0 L
By Charles' law V₁/T₁ = V₂/T₂, so V₂ = 2.0 × 450 ÷ 300 = 3.0 L.Which of these gases is adsorbed to the greatest extent on a solid adsorbent such as charcoal?
Chapter 11: Adsorption and Colloids
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Answer: D. NH₃
Easily liquefiable gases (high critical temperature) such as NH₃, SO₂ and Cl₂ are adsorbed much more than H₂, N₂ and O₂.A radioactive sample of 80 g has a half-life of 5 days. How much of it remains undecayed after 15 days?
Chapter 13: Nuclear Chemistry and Radioactivity
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Answer: A. 10 g
15 days = 3 half-lives, so 80 → 40 → 20 → 10 g remains.What is the hybridization of the positively charged carbon atom in a carbocation?
Chapter 14: Basic Principles of Organic Chemistry
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Answer: B. sp²
The carbocation carbon is sp² hybridized with trigonal planar geometry; its unhybridized pz orbital is vacant.
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All questions are written by PadhaiNotes in our own words from the chapters of the official Maharashtra State Board Balbharati textbook (ebalbharati.in). Each question shows its chapter.